Posted by Walker on Monday, August 20, 2012 at 9:46am.
A limiting reagent problem.
Na2CO3 + Ca(NO3)2 ==> CaCO3 + 2NaNO3
mol Na2CO3 = M x L = 0.200 x 0.100 = 0.02
mol Ca(NO3)2 = M x L = 0.100 x 0.200 = 0.02 mol.
Calculate how much CaCO3 is formed if we use 0.02 mol Na2CO3 and all the Ca(NO3)2 needed. That will be
0.02 mol Na2CO3 x (1 mol CaCO3/1 mol Na2CO3) = 0.02 mol CaCO3 formed.
Next calculate how much CaCO3 is formed if we use 0.02 mol Ca(NO3)2 and all the Na2CO3 needed. That will be
0.02 mol Ca(NO3)2 x (1 mol CaCO3/1 mol Ca(NO3)2) = 0.02 mol.
Since the number is the same (0.02 mol CaCO3), neither Ca(NO3)2 nor Na2CO3 is the limiting reagent and 0.02 mol CaCO3 is formed.
g CaCO3 = mols x molar mass = ?
Related Questions
Chem - Solutions of sodium carbonate and silver nitrate react to form solid ...
chemistry - In Chemistry: what is ph during the titration of 20.00ml of 0.1000m ...
chemistry - Write the correct equation for the formation of a white precipitate ...
Stoichometry - Solutions of sodium carbonate and silver nitrate react to form ...
chemistry - A precipitate of calcium phosphate is formed when aqueous solutions ...
Chemistry - Given one of the following solution: 50.00mL of 0.10M of K2CrO4 ...
Chemistry - A buffer solution is made as followed: i)adding 13.50mL of 0.200mol...
chem - What is the pH of a solution prepared by diluting 25.00mL of 0.020M ...
Chemisty - Calculate the mass of water in grams that could be produced from the ...
General Chemistry - Change these word equations into formula equations and ...
For Further Reading
