Balance the equation and then write the net ionic equation a. (NH4)2 CO3(aq) + Cu(NO3)2(aq) to CuCO3(s) + NH4NO3(aq)

To balance the equation (NH4)2CO3(aq) + Cu(NO3)2(aq) → CuCO3(s) + NH4NO3(aq), we first need to make sure that the number of each type of atom is the same on both sides of the equation.

1. Start by counting the number of atoms for each element on both sides:
Left side: 2 N, 8 H, 2 C, 6 O
Right side: 2 N, 4 H, 1 C, 6 O

2. Balance the elements that appear in one compound on each side first. In this case, we can balance the nitrogen and carbon atoms:
(NH4)2CO3(aq) + Cu(NO3)2(aq) → CuCO3(s) + 2 NH4NO3(aq)

3. Now let's balance the hydrogen and oxygen atoms:
(NH4)2CO3(aq) + Cu(NO3)2(aq) → CuCO3(s) + 2 NH4NO3(aq)

The equation is now balanced.

Next, let's write the net ionic equation. A net ionic equation shows only the species that participate in the chemical reaction, excluding spectator ions. In this case, we have ammonium (NH4+) and nitrate (NO3-) ions, which are spectator ions.

The net ionic equation for the reaction is:
Cu(2+)(aq) + CO3(2-)(aq) → CuCO3(s)

Note: We ignored any other reactions or changes that might occur in the solution, such as dissociation of the compounds. This is a simplified representation of the net ionic equation based on the given reaction.

To balance the chemical equation, we need to ensure that the number of each type of atom is the same on both sides of the equation. Let's start by balancing the equation:

(NH4)2CO3(aq) + Cu(NO3)2(aq) → CuCO3(s) + 2NH4NO3(aq)

Now that the equation is balanced, we can write the net ionic equation by removing any spectator ions that do not participate in the reaction. In this case, the spectator ions are the ammonium (NH4+) ions and nitrate (NO3-) ions since they appear unchanged on both sides of the equation. The net ionic equation includes only the species that undergo a change. Let's write the net ionic equation:

Cu2+(aq) + CO3^2-(aq) → CuCO3(s)

Therefore, the net ionic equation for (NH4)2CO3(aq) + Cu(NO3)2(aq) to CuCO3(s) + NH4NO3(aq) is Cu2+(aq) + CO3^2-(aq) → CuCO3(s).

(NH2)2CO3 + Cu(NO3)2 -> CuCO3 + 2NH4NO3

Getting rid of the spectator NH4 and NO3 ions, we are left with

Cu2+(aq) + CO32-(aq) -> CuCO3(s)