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December 18, 2014

December 18, 2014

Posted by **alli** on Sunday, August 19, 2012 at 8:00pm.

the vertex is (1,-3)

y intercept is -2

please show work so i can see how this is done, thank you!

- college algebra -
**Anonymous**, Sunday, August 19, 2012 at 9:36pmFor a vertex of (1,-3) the equation is

Y= a(x-1)^2 - 3

But (0,-2)lies on it, so

-2 = a(0-1)^2 -3

1 = a

Y = (x-1)^2 - 3

- college algebra -
**jermaine**, Monday, April 14, 2014 at 12:36pmFind the equation of the quadratic Functions whose graph is a parabola the points (-2,19), (3,14) and (4,25)

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