Posted by **ashley** on Sunday, August 19, 2012 at 4:27pm.

a tugboat goes 160 miles upstream in 20 hours. The return trip downstream takes 5 hours. Find the speed of the tugboat without a current and the speed of the current.

- alegbra -
**Steve**, Sunday, August 19, 2012 at 7:24pm
if tugboats speed is s, and current is c,

since the distances are the same, and

distance = speed * time,

(s-c)*20 = (s+c)*5 = 160

20s - 20c = 160

5s + 5c = 160

or,

20s+20c = 640

40s = 800

s = 20

c = 12

check:

160/32 = 5

160/8 = 20

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