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April 19, 2014

Homework Help: chem

Posted by greeny on Sunday, August 19, 2012 at 1:14pm.

the combustion of 1.83 grams of a compound which only contains C,H, and O yields 4.88 grams of CO2, and 1.83 grams of H2O. What is the empirical formula of this compound?

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4.88 g CO2 x 1 mol CO2/44.01 g CO2 x 2 mol O2= .2217 mol O2

1.38 g of H20 x 1mol H20/ 18.02 g H20 x 2 mol H2/ 1 mol H20= .15316 mol H2


How do I get find mols of C? What is the 1.83 grams used for? thanks!

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