Posted by Fai on Saturday, August 18, 2012 at 10:20pm.
I would consider this.
If the solution is 65% by volume EtOH, then in 1 L soln there are 650 mL EtOH. Since mass = volume x density, then the mass of EtOH in the L is 650 mL x 0.789 g/mL = 512.9 g.
Then (512.9/1000)*100 = 51.3% w/v.
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