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November 24, 2014

November 24, 2014

Posted by **alli** on Saturday, August 18, 2012 at 10:14pm.

Please show work so i can understand this. thank you

- college algebra -
**Henry**, Sunday, August 19, 2012 at 5:53pmF(x) = Y = x^2 - 8x + 15.

h = Xv = -B/2A = 8 / 2 = 4.

K = Yv = 4^2 - 8*4 + 15 = -1.

V(h,k) = V(4,-1).

Axis = h = 4.

The intercepts are the value of X when

Y = 0:

Y = x^2 - 8x + 15 = 0

C = 15 = (-1)*(-15) = (-3)*(-5).

We select -3 and -5 for factoring because the sum = B(-8).

(x-5)(x-3) = 0

x-5 = 0

X = 5.

x-3 = 0

X = 3.

Intercepts(Solution set): X = 5, and 3.

To graph the function, select values of X below and above h; and calculate the

corresponding value of Y.

(x,y). Y = x^2 - 8x + 15.

(1,8).

(2,3).

(3,0).

V(4,-1).

(5,0).

(6,3).

(7,8).

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