the sum of 2 numbers is 77. one number is 2 1/2 times as big as the other number.find the difference between the 2 addends.please show how you got your answer.

my answer is 72.6, am i right if not please tell me why and how.

the numbers are n and 5/2 n

add them up to get 77:

n + 5/2 n = 77
7/2 n = 77
n = 22

the numbers are 22 and 55

Let the two numbers be x and 2.5x. Their difference is 1.5x

3.5x = 77
x = 22
2.5x = 55
The difference is 1.5x = 33

Your answer is incorrect.

one number form 75 is 100

To find the difference between the two addends, we first need to set up a system of equations to represent the given information.

Let's call the smaller number "x" and the larger number "2.5x" since it is stated that one number is 2 1/2 times as big as the other number.

The sum of the two numbers is 77, so we can set up the equation:

x + 2.5x = 77

To solve this equation, we combine like terms:

3.5x = 77

Next, we isolate the variable by dividing both sides of the equation by 3.5:

x = 77 / 3.5

Evaluating this expression gives us:

x ≈ 22

So the smaller number is approximately 22.

To find the larger number, we multiply the smaller number by 2.5:

2.5x = 2.5 * 22 ≈ 55

So the larger number is approximately 55.

Finally, to find the difference between the two addends, we subtract the smaller number from the larger number:

55 - 22 = 33

Therefore, the difference between the two addends is 33, not 72.6.