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November 20, 2014

November 20, 2014

Posted by **wan** on Saturday, August 18, 2012 at 8:00am.

- math -
**Reiny**, Saturday, August 18, 2012 at 8:54amWhen they meet,

let the number of laps covered by John (the slower) be n

So number of sections covered by John = 12n

In that same time, Tom has covered 12n-4 sections

Time = distance/rate

Tom's time = 12n/2

John's time = (12n-4)/1

12n/2 = 12n-4

6n = 12n-4

6n=4

n= 2/3

He will catch him at the 8 section mark of the first lap

Tom's time = 12n/2 = 6n = 6(2/3) = 4 units of time

John's time = (12n-4)/1 = 12(2/3)-4 = 4 units of time ----- ✔

Tom's rate = Tom's distance/4 = 8/4 = 2 units of distance/units of time

John's rate = 4/4 = 1 unit of distance/time ---- ✔

- math -
**wan**, Sunday, August 19, 2012 at 9:43pmthis is a little bit hard,still not understand

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