Friday

February 27, 2015

February 27, 2015

Posted by **wan** on Saturday, August 18, 2012 at 8:00am.

- math -
**Reiny**, Saturday, August 18, 2012 at 8:54amWhen they meet,

let the number of laps covered by John (the slower) be n

So number of sections covered by John = 12n

In that same time, Tom has covered 12n-4 sections

Time = distance/rate

Tom's time = 12n/2

John's time = (12n-4)/1

12n/2 = 12n-4

6n = 12n-4

6n=4

n= 2/3

He will catch him at the 8 section mark of the first lap

Tom's time = 12n/2 = 6n = 6(2/3) = 4 units of time

John's time = (12n-4)/1 = 12(2/3)-4 = 4 units of time ----- ✔

Tom's rate = Tom's distance/4 = 8/4 = 2 units of distance/units of time

John's rate = 4/4 = 1 unit of distance/time ---- ✔

- math -
**wan**, Sunday, August 19, 2012 at 9:43pmthis is a little bit hard,still not understand

**Answer this Question**

**Related Questions**

math - In a motorcycle race, one lap of the course is 650 m. At the start of the...

math - In a motorcycle race, one lap of the course is 650 m. At the start of the...

Biomechanics - John and Al are in a 15 km race. John averages 4.4 m/s during the...

Basic Biomechanics - John and Al are in a 15 km race. John averages 4.4 m/s ...

English - 1. He has as many books as Tom. 2. He has as much money as Tom. 3. He ...

Science/Math - John and Al are in a 15 km race. John averages 4.4 m/s during the...

Science/Math - Word Problem page 19 John and Al are in a 15 km race. John ...

Math - Tom can complete 5 laps of a race track in 15 minutes. Mark can finish 10...

geometry - A circular garden is divided into 6 equal sections. The radius of the...

Math - Sally runs 2.8 m/s. John runs 1.9 m/s. if John has a 30 m head start. How...