Tuesday

September 16, 2014

September 16, 2014

Posted by **Pat** on Thursday, August 16, 2012 at 3:38pm.

Absolute value :

1. |x^2-2x+16|=8

x=-4

x=-3

x=-2

x=2

2.|3x-2|=7

x=5\3

x=3

3. |3x+2|+3=0

x= -5/3

- Algebra2 -
**Reiny**, Thursday, August 16, 2012 at 4:44pm1.

x^2 - 2x + 16 = 8 or x^2 - 2x + 16 = -8

x^2 - 2x + 8 = 0 or x^2 - 2x + 24 = 0

neither the first nor the second has a real solution.

2. |3x-2| = 7

3x-2=7 or 3x-2=-7

3x=9 or 3x = -5

x = 3 or x = -5/3

3.

|3x+2| = -3

by its very definition, there cannot be a solution here.

- Algebra2 -
**Unknown.**, Friday, August 17, 2012 at 11:03amIn the first problem it was suppose to be -16

my mistake, but does it still g=have no solution?

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