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December 18, 2014

December 18, 2014

Posted by **steven g. rosario** on Thursday, August 16, 2012 at 5:30am.

- math -
**Bosnian**, Thursday, August 16, 2012 at 8:23amd = your digit

d = 100 x + 10 y + z

my hundreds digit is three more than my ones

x = z + 3

that is equivalent with :

z = x - 3

my tens digit is oneless than my hundreds

y = x - 1

d = 100 x + 10 y + z

d = 100 * x + 10 * ( x - 1 ) + x - 3

d = 100 x + 10 x - 10 + x - 3 = 111 x - 13

Solution 1 :

x = 9

y = x - 1 = 9 - 1 = 8

z = x - 3 = 9 - 3 = 6

d = 986

Solution 2 :

x = 8

y = x - 1 = 8 - 1 = 7

z = x - 3 = 8 - 3 = 5

d = 875

Solution 3 :

x = 7

y = x - 1 = 7 - 1 = 6

z = x - 3 = 7 - 3 = 4

d = 764

Solution 4 :

x = 6

y = x - 1 = 6 - 1 = 5

z = x - 3 = 6 - 3 = 3

d = 653

Solution 5 :

x = 5

y = x - 1 = 5 - 1 = 4

z = x - 3 = 5 - 3 = 2

d = 542

Solution 6 :

x = 4

y = x - 1 = 4 - 1 = 3

z = x - 3 = 4 - 3 = 1

d = 431

Solution 7 :

x = 3

y = x - 1 = 3 - 1 = 2

z = x - 3 = 3 - 3 = 0

d = 320

- math -
**Reiny**, Thursday, August 16, 2012 at 8:28amJust start by putting 0, 1,2, ... into the ones digit

then fulfilling the other two conditions

320

431

542

653

764

875

986 , can't use 7 or higher for the unit digits

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