Wednesday

August 20, 2014

August 20, 2014

Posted by **jhon** on Thursday, August 16, 2012 at 2:58am.

a) explain how the above paragraph gives information not only about the speed of the boat but also about its velocity.

b) draw a vector diagram showing the velocity of the boat and the velocity of the current. Use the diagram to find

i) the magnitude of the resultant velocity

ii) the angle between due north and the direction of travel of the boat.

c) calculate the distance the boat now travels in 5 mins;

d) mass of boat is 3.0 x 103kg (3000kg). Calculate the additional force that needs to be applied to give the boat an initial acceleration of 2.5 x 10-2m/s2 (0.025 m/s2).

- physics -
**Henry**, Thursday, August 16, 2012 at 7:40pma. When both speed and direction are

given, we call it velocity.

b. Draw a vector from the origin

pointihg due north to represent the velocity of the boat

Draw a vector from the origin 45o South of West(225o) to represent the velocity of the current.

1. Vr = 3m/s @ 90o + 2m/s @ 225o = Resultant velocity.

X = Hor. = 2*cos225 = -1.414 m/s.

Y = Ver. = 3 + 2*sin225 = -1.586 m/s.

(Vr)^2 = X^2 + Y^2 = 2 + 2.5 = 4.5

Vr = 2.12 m/s. = Resultant velocity.

2. cosA= X/Vr=-1.586 / 2.12 = -0.66708

A = 132o. = Direction of travel of boat.

132 - 90 = 42o Between North and direction of travel of boat.

c. 5min. = 300 s.

d = Vr*t = 2.12m/s * 300s = 636 m.

3.

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