Calculate the rate of heat required to bring 1.80mol/hr of HBr gas from 37.0 C to 434.0C at atmospheric pressure
(Heat capacity of HBr is described by eq.)
Cp (kJ/mol * C) = a + bT + cT^2 + dt^3
T is in C and HBr - a = 2.910x10^-2, b= -2.27x10^-7, c= 9.887x10^-9, and d= -4.858x10^-12
To calculate the rate of heat required to bring HBr gas from one temperature to another, you can use the formula:
Q = n × Cp × ΔT
Where:
Q is the heat required (in kJ)
n is the number of moles of HBr gas
Cp is the molar heat capacity of HBr gas (in kJ/mol * °C)
ΔT is the change in temperature (in °C)
In this case, n = 1.80 mol/hr, Cp is defined by the equation, and ΔT = (434.0°C - 37.0°C) = 397.0°C.
Now, let's substitute the given values into the equation and calculate the rate of heat required:
Cp = a + bT + cT^2 + dT^3
Cp = (2.910x10^-2) + (-2.27x10^-7)T + (9.887x10^-9)T^2 + (-4.858x10^-12)T^3
Q = (1.80 mol/hr) × [(2.910x10^-2) + (-2.27x10^-7)T + (9.887x10^-9)T^2 + (-4.858x10^-12)T^3] × (397.0°C)
By substituting the values of T and evaluating the equation, you will get the rate of heat required in kJ/hr.