Posted by Robert on Tuesday, August 14, 2012 at 11:56pm.
the character that doesn't show up is the emf (E)
The current is
i = dq/dt = C*E*(1/RC)*e^(-t/RC)
= (E/R)*e^(-t/RC)
iR + q/C = E*e^(-t/RC)+ E*(1 – e^-t/RC)
= E
Therefore the sum of the voltage drop across the capacitor and the resistor equals E at all times, as required.
thank you very much drwls, this is a question from a sample exam, getting ready for my finals tomorrow!
Good luck with finals! I took a lazy approach to your question, showing that what you wrote is the solution, rather than solving the general differential equation.
thanks. It's all good, I understand your approach and I really appreciate it!
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