Posted by Kameesha on Tuesday, August 14, 2012 at 1:45pm.
1. Find the domain of the composite function f o g. f(x)= 2/x3; g(x)= 7/x
2. Solve the following exponential equation. Exact answers only. 2^19x = e^2x

College Algebra  Steve, Tuesday, August 14, 2012 at 1:55pm
f(g(x)) = 2/(g(x)3) = 2/(7/x)3) = 2x/(73x)
domain would be all reals except x = 7/3, but we have to recall that g(x) is not defined for x=0.
So the domain of fog is all reals except 0, 7/3
2^(19x) = e^2x
take log of both sides, recalling that ln(a^b) = b*lna:
(19x)ln2 = 2x
ln2  9 ln2 * x = 2x
2x + 9 ln2*x = ln2
x = ln2/(2+9 ln2)
or, if you want to be sneaky,
ln2/(ln(e^2) + ln(2^9))
= ln2/ln(512e^2)
= log_{512e^2}2

College Algebra  Jai, Tuesday, August 14, 2012 at 2:04pm
1.
fog(x) = 2 /[(7/x)  3]
simplifying,
2x/(7  3x)
Domain: all real numbers except 3, 0 and 7/3
2.
2^(19x) = e^(2x)
get ln of both sides:
ln 2^(19x) = ln e^(2x)
(19x)*(ln 2) = 2x
(19x)/(2x) = 1/(ln 2)
1/(2x)  9/2 = 1/(ln 2)
1/(2x) = 1/(ln 2) + 9/2
2x = 1/[1/(ln 2) + 4.5]
x = 1/[2(1/ln 2 + 4.5)]
x = 1/[2/(ln 2) + 9]
x = 1 / [2/(ln 2) + 9(ln 2) / (ln 2)]
x = 1 / [2 + 9(ln 2)] / ln 2
finally,
x = (ln 2)/(2 + (9 ln 2))
hope this helps~ :)
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