Posted by **Alex** on Monday, August 13, 2012 at 1:00pm.

Find k, given that (2,k) is equidistant from (3,7) and (9,1).

The answer is : k=0

How do I solve this problem?

- Algebra -
**Steve**, Monday, August 13, 2012 at 3:21pm
The slope of the line segment joining (3,7) and (9,1) is -6/6 = -1.

Any point equidistant from those two points will lie on the perpendicular bisector of that line segment.

So, we want the line with slope=1, through (6,4), the midpoint of the segment.

y-4 = 1(x-6)

Now, we plug in (2,k) to get

k-4 = 2-6

k = 0

## Answer this Question

## Related Questions

- Algebra - Find all intervals on which the given expressions are positive. (x-1)(...
- algebra - Explain in your own words what it means for an equation to model a ...
- Geo (locus) - I don't fully get this stuff but some of these I guessed on and ...
- Algebra - I was given this problem to solve and no matter what order I multiply ...
- Algebra II - Find the solution if possible. If there is not enough information ...
- Analytic Geometry - A point is equidistant from (-2,4) and (3,5). It is also ...
- Analytic Geometry - A point is equidistant from (-2,4) and (3,5). It is also ...
- Algebra 2 - Given f(x)= x^2+7x+8, find x when f(x)= -4. My answer is -4. Find x ...
- Algebra - Please help me to solve this problem. Thank you in advance for helping...
- maths - The probability that Katarina will correctly solve a given Brilliant ...

More Related Questions