Posted by Alex on Monday, August 13, 2012 at 1:00pm.
The slope of the line segment joining (3,7) and (9,1) is -6/6 = -1.
Any point equidistant from those two points will lie on the perpendicular bisector of that line segment.
So, we want the line with slope=1, through (6,4), the midpoint of the segment.
y-4 = 1(x-6)
Now, we plug in (2,k) to get
k-4 = 2-6
k = 0
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