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October 22, 2014

October 22, 2014

Posted by **Becky** on Monday, August 13, 2012 at 12:56pm.

C(v) : (700v^2 + 34500)/v

C'(v): (700v^2 - 34500)/v^2

C"(v): 69000/v^3

Question: To minimize the total cost of the journey the ship should travel at a speed of _____km/h

Correct to 3 significant figures.

(The speed that minimizes the total cost that have calculated correspond to a zero of the derivative of the total cost. The minimum of the total cost will (for this problem) occur at a turning point of the total cost function)

ANYONE HELP???

- calculus -
**Steve**, Monday, August 13, 2012 at 3:11pmtime spent is 100/v

C(v) = 7v^2 * 100/v + 345 * 100/v

= 700v + 34500/v (your C(v) is correct)

However, your C' is way wrong.

C'(v) = 700 - 34500/v^2

set C'(v)=0, to get v=√(345/7) = 7.02 km/hr

Better question would have asked for the speed in knots: 3.79

Must be a barge!

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