Thursday

April 24, 2014

April 24, 2014

Posted by **Anonymous150** on Monday, August 13, 2012 at 11:18am.

Solve for k.

a. 3/2

b. 5/3

c. 2

d. 3

e. 5

I think when simplified its (a^12)^k = (a^3)^(k+5)

but i don't know how to get k from here. How do you solve for these kind of exponents?

- Math -
**Steve**, Monday, August 13, 2012 at 11:24ama^12 = (a^3)^4, so

(a^3)^(4k) = (a^3)^(k+5), so

4k = k+5

k = 5/3

- Math -
**Anonymous150**, Monday, August 13, 2012 at 11:29amThank you so much :D

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