Posted by Becky on Monday, August 13, 2012 at 5:17am.
how to find the second derivative of quotient rule?
f(x): 700v^2 + 3450/v
f'(x) : 700v^2 3450/v^2
f"'(x) : ???

calculus  Becky, Monday, August 13, 2012 at 5:21am
sorry typo error above, question is,
f(x): 700v^2 + 34500/v
f'(x) : 700v^2 34500/v^2
f"'(x) : ???

calculus  Reiny, Monday, August 13, 2012 at 9:08am
the way you typed it ....
f'(x) = 1400v  3450/v^2 or 1400v  3450v^2
f''(x) =1400 + 6900v^3
IF you meant f(x) = (700v^2 + 3450)/v
I would change it to
f(x) = 700v + 3400v^1
f'(x) = 700  3400v^2
f''(x) = 6800v^3 or 6800/v^2

calculus  Becky, Monday, August 13, 2012 at 10:52am
The question should be:
f(x): 700v^2 + 34500/v
f'(x) : 700v^2 34500/v^2
f''(x) : ???

calculus  Reiny, Monday, August 13, 2012 at 12:22pm
You missed my point, the issue was not whether it was 3450 or 34500, the point was the use of brackets.
Did you not look at my reply?
simply change 3450 to 34500 and follow the steps.
You derivative would be correct if you had placed it in brackets , such as
f'(x) = (700v^2  34500)/v^2
which would reduce to
f'(x) = 700  34500/v^2 = 700  34500v^2
then f''(x) = 69000/v^3

calculus  Becky, Monday, August 13, 2012 at 12:25pm
pls ignore the above question...
to make it clearer for the question, it is...
f(x): (700v^2 + 34500)/v
f'(x) : (700v^2 34500)/v^2
f''(x) : ???

calculus  Becky, Monday, August 13, 2012 at 12:31pm
i got the answer!! thank you!!!
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