Posted by Becky on .
how to find the second derivative of quotient rule?
f(x): 700v^2 + 3450/v
f'(x) : 700v^2 3450/v^2
f"'(x) : ???

calculus 
Becky,
sorry typo error above, question is,
f(x): 700v^2 + 34500/v
f'(x) : 700v^2 34500/v^2
f"'(x) : ??? 
calculus 
Reiny,
the way you typed it ....
f'(x) = 1400v  3450/v^2 or 1400v  3450v^2
f''(x) =1400 + 6900v^3
IF you meant f(x) = (700v^2 + 3450)/v
I would change it to
f(x) = 700v + 3400v^1
f'(x) = 700  3400v^2
f''(x) = 6800v^3 or 6800/v^2 
calculus 
Becky,
The question should be:
f(x): 700v^2 + 34500/v
f'(x) : 700v^2 34500/v^2
f''(x) : ??? 
calculus 
Reiny,
You missed my point, the issue was not whether it was 3450 or 34500, the point was the use of brackets.
Did you not look at my reply?
simply change 3450 to 34500 and follow the steps.
You derivative would be correct if you had placed it in brackets , such as
f'(x) = (700v^2  34500)/v^2
which would reduce to
f'(x) = 700  34500/v^2 = 700  34500v^2
then f''(x) = 69000/v^3 
calculus 
Becky,
pls ignore the above question...
to make it clearer for the question, it is...
f(x): (700v^2 + 34500)/v
f'(x) : (700v^2 34500)/v^2
f''(x) : ??? 
calculus 
Becky,
i got the answer!! thank you!!!