Posted by **Robert** on Sunday, August 12, 2012 at 11:52pm.

A square loop (length along one side = 20 cm) rotates in a constant magnetic field which has a magnitude of 2.0 T. At an instant when the angle between the field and the normal to the plane of the loop is equal to 20 and increasing at the rate of 10/s, what is the magnitude of the induced emf in the loop?

The answer is 4.8 mV, but I keep getting 2.7

I used E = NABwsin(wt)

Because we have no coil, we can take out N so that leave sus with BAwsin(wt)

What am I doing wrong?

THank you

## Answer This Question

## Related Questions

- Physics - A square conducting loop with sides of length L is rotation at a ...
- Physics - A square conducting loop with sides of length L is rotation at a ...
- Physics - A square conducting loop with sides of length L is rotation at a ...
- Physics - A square conducting loop with sides of length L is rotation at a ...
- physics - A square loop of wire of side 2.8 cm carries 3.0 A of current. A ...
- Physics - A square loop of wire of side 3.0 cm carries 3.0 A of current. A ...
- magnetic field - A square loop with resistance R=0.001 Ohms,mass 1.0 gram, and ...
- physics - A loop of surface area s1=10cm^2 placed ina uniform magnetic field Bof...
- Physic please help! - I got the correct answer for part (a) but I am unsure of ...
- physics - A rectangular loop of wire with sides 0.196 and 0.584 m lies in a ...

More Related Questions