Tuesday

October 21, 2014

October 21, 2014

Posted by **Robert** on Sunday, August 12, 2012 at 11:52pm.

The answer is 4.8 mV, but I keep getting 2.7

I used E = NABwsin(wt)

Because we have no coil, we can take out N so that leave sus with BAwsin(wt)

What am I doing wrong?

THank you

- Physics - Electromagnetism -
**Elena**, Monday, August 13, 2012 at 1:42amω= Δα/Δt =10º/s=π/18 rad/s.

A=a²=0.04 m²,

ωt=20º

E=- dΦ/dt = - d(B•A•cos(ωt))/dt =

= B•A• ω•sin(ωt) =

=2•0.04• (π/18) •sin20º = 4.775•10^-3 V ≈4.8 mV

**Answer this Question**

**Related Questions**

physics - A square loop of wire of side 2.8 cm carries 3.0 A of current. A ...

Physics - A square conducting loop with sides of length L is rotation at a ...

Physics - A square conducting loop with sides of length L is rotation at a ...

Physics - A square conducting loop with sides of length L is rotation at a ...

Physics - A square conducting loop with sides of length L is rotation at a ...

physics - A rectangular wire loop of dimensions a×b, with a=3.5 cm and b=4.5 cm...

magnetic field - A square loop with resistance R=0.001 Ohms,mass 1.0 gram, and ...

PHYSICS - A circular loop of flexible iron wire has an initial circumference of ...

physics - A rectangular loop of wire with sides 0.196 and 0.584 m lies in a ...

magnets - A square loop of wire of side L with total resistance R moves at ...