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January 31, 2015

January 31, 2015

Posted by **Robert** on Sunday, August 12, 2012 at 11:52pm.

The answer is 4.8 mV, but I keep getting 2.7

I used E = NABwsin(wt)

Because we have no coil, we can take out N so that leave sus with BAwsin(wt)

What am I doing wrong?

THank you

- Physics - Electromagnetism -
**Elena**, Monday, August 13, 2012 at 1:42amω= Δα/Δt =10º/s=π/18 rad/s.

A=a²=0.04 m²,

ωt=20º

E=- dΦ/dt = - d(B•A•cos(ωt))/dt =

= B•A• ω•sin(ωt) =

=2•0.04• (π/18) •sin20º = 4.775•10^-3 V ≈4.8 mV

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