Posted by Fai on .
A 0.446g sample of an unknown monoprotic acid was titrated with 0.105M KOH the molar mass is 120g/mol. What is the pka value?
0.105M x 0.446g = 0.04683 x 1000 =46.83
46.83 x 120 = 56196 changes 5.6gm
This answer 5.6gm I am not sure answer. Pls help
5.6 g is not a pKa. I don't think there is enough information to solve this problem.