Tuesday

September 30, 2014

September 30, 2014

Posted by **ibranian** on Saturday, August 11, 2012 at 11:13pm.

- math -
**Steve**, Sunday, August 12, 2012 at 2:12pmDraw a diagram. Let P be the point on shore where the pipe goes underwater.

Then if D is the drill rig, and R is the refinery,

x^2 = 12^2 + (20-y)^2

and the cost is

c = 50x+30y

c = 50√(144 + (20-y)^2) + 30y

dc/dy = 50(y-20)/√(y^2 - 40y + 544) + 30

dc/dy=0 when

y = 11

so, x = 15

**Answer this Question**

**Related Questions**

Calculus - An offshore well is 2 miles off the coast. The refinery is 4 miles ...

Math(module 4 Calculus) - (minimum commuting time) A lighthouse lies 2 miles ...

Calculus - Optimization An offshore oil well is 2km off the coast. The refinery ...

Calculus - You are in a boat "a" miles from the nearest point on the coast. You ...

Calculus - A man is in a boat 4 miles off a straight coast. He wants to reach a ...

math - a man is in a boat 2 miles from the nearest point on the coast. He is to...

calculus - Given ensuing information, determine the least cost and the least ...

math - an athlete. an run in 6 miles in 51 minutes. at this rate approximately ...

math - on a drive through allegheny county,natalie drove due west for 9 miles,...

HELP!! MATH - A boater finds herself 4 miles fromm the nearest point on a ...