Posted by ibranian on Saturday, August 11, 2012 at 11:13pm.
Draw a diagram. Let P be the point on shore where the pipe goes underwater.
Then if D is the drill rig, and R is the refinery,
x^2 = 12^2 + (20-y)^2
and the cost is
c = 50x+30y
c = 50√(144 + (20-y)^2) + 30y
dc/dy = 50(y-20)/√(y^2 - 40y + 544) + 30
dc/dy=0 when
y = 11
so, x = 15
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