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February 27, 2015

February 27, 2015

Posted by **karen** on Saturday, August 11, 2012 at 5:03pm.

1.) A random digit from 1 to 9 (inclusive) is chosen, with all digits being equally likely. The probability that when it's squared it will end with the digit 1.

2.) A random number between 1 and 20 (inclusive) is chosen. The probability that its square root will not be an integer.

- math -
**MathMate**, Saturday, August 11, 2012 at 10:12pmSee response to:

http://www.jiskha.com/display.cgi?id=1344678011

and post if you need more explanations or would like to post your attempt.

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**karen**, Sunday, August 12, 2012 at 5:37pmthank you for your help!

can you check if it's correct?

1.) 1/9

2.) 4/2= 1/5

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**MathMate**, Sunday, August 12, 2012 at 6:33pm1.

Note that

21*21=441

49*49=2401

Does that give you a hint?

2.

The question looks for

"The probability that its square root will**not**be an integer"

so check your answer accordingly.

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**Anna**, Thursday, August 21, 2014 at 11:27amQuestion: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22

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**Anna**, Thursday, August 21, 2014 at 11:30amQuestion: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22

@MathMate

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