Thursday
April 24, 2014

Homework Help: Chemistry

Posted by Fai on Saturday, August 11, 2012 at 1:57pm.

A solution of is prepared by adding 50.3ml of concentrated hydrochloric acid and 16.6ml of concentrated nitric acid to 300ml of water. More water is added until the final volume is 1.00L.
Calculate (H+) (OH) and the PH for this solution. Hint concentrated HCL is 38% hcl by mass and has a density 1.19g/ml.
Concentrated HN03 is 70% HN03 and has a density of 1.42g/ml

My calculation
1.19g/ml x 1000ml x 0.38/36.46 = 12M (HCL)
1.42g/ml x 1000ml x 0.7/63.01 = 16M (HN03)
(HCL) 50.3 x 12M = 604ml
(HN03) 16.6ml x 16M = 265.6ml

I am not completed. Who helps me to solve it for me. Pls help

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