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April 21, 2015

April 21, 2015

Posted by **Albert** on Saturday, August 11, 2012 at 11:37am.

#2. Add:

3p^2 – 5p – 4 and 9p^2 + 10p – 2

A. 12p2 + 15p – 6

B. 12p2 + 5p – 2

C. 12p2 + 5p – 6

D. 12p2 + 15p – 2

answer D

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#7.

(3x^2 – 2x – 1)(x^2 + x + 5)

A. 3x^4 + 2x^3 + 12x^2 – 11x – 5

B. 3x^4 + x^3 + 12x^2 – 10x – 5

C. 3x^4 + x^3 + 12x^2 – 11x – 5

D. 3x^4 + x^3 + 14x^2 – 11x – 5

Answer is B

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#9.

Factor completely relative to the integers.

x^2 – 8x + x – 8

A. (x + 8)(x – 1)

B. (x – 8)(x – 1)

C. (x + 1)(x + 8)

D. (x – 8)(x + 1)

Answer D.

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#10. Factor completely relative to the integers.

25x^2 – 5x – 2

A. (5x – 2)(5x + 1)

B. (5x + 2)(5x – 1)

C. (25x – 2)(x + 1)

D. (5x + 1)(5x – 2)

Answer B.

_______________________________

- Algebra -
**Steve**, Saturday, August 11, 2012 at 12:56pm#2. No. (C):

-5p+10p = +5p, not +15p

-4 -2 = -6

#7. No. (C):

-2x(5) - 1(x) = -11x

#9. Yes!

#10. No. (D)

you want -10x, and +1(5x) + 5x(-2) = -10x

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