Posted by Paul on Friday, August 10, 2012 at 2:02pm.
Evaluate the following definite integral:
integral at a = -1, b=2
Would I have to separate them in 3 terms as:
-4 ∫1/9x^2 + ∫1/30x + ∫1/25
resulting in: -4/(3x^3)+ (15x^2)+ C?
and from there I can replace a and b
f(a) - f(b)?
Calculus - Steve, Friday, August 10, 2012 at 4:27pm
1/(a+b+c) is NOT 1/a + 1/b + 1/c
What you need to do is let
u = 3x+5 and you have
du = 3 dx, so dx = du/3
x in [-1,2] means u in [2,11]
∫[2,11] -4/u^2 du/3
-4/3 ∫[2,11] u^-2 du
That should be ever so simple.
Calculus - Paul, Friday, August 10, 2012 at 6:23pm
THanks Steve, but why 3x+5??
Calculus - Steve, Saturday, August 11, 2012 at 5:54am
because you have 9x^2 + 30x + 25 = (3x+5)^2
Answer This Question
More Related Questions
- Calculus II - So I'm trying to integrate a function using partial fractions. ...
- COLLEGE CALCULUS. HELP! - Evaluate the definite integral ∫(0,2) (x-1)^25 ...
- Calculus III - Use symmetry to evaluate the double integral ∫∫R(10+x...
- calculus - a) Let f(z) = z^2 and γ(t) = 1 + it^3, t ∈ [0,1]. i) Write...
- Calculus 2 correction - I just wanted to see if my answer if correct the ...
- Calculus - Evaluate the triple integral ∫∫∫_E (x+y)dV where E ...
- Calculus - Evaluate the triple integral ∫∫∫_E (x)dV where E is...
- Calculus - Alright, I want to see if I understand the language of these two ...
- Calculus - Evaluate the triple integral ∫∫∫_E (xy)dV where E ...
- Calculus - Evaluate the triple integral ∫∫∫_E (z)dV where E is...