Thursday

October 23, 2014

October 23, 2014

Posted by **Timofey** on Friday, August 10, 2012 at 10:48am.

1 + 5 + 9 + … + (4n -3)= n(2n-1)

- Calculus -
**Steve**, Friday, August 10, 2012 at 11:07amfor k=1: 1 = 1(2-1)

assume for k

for n=k+1,

1+5+...+(4k-3)+(4(k+1)-3) = k(2k-1) + (4(k+1)-3)

= k(2k-1) + (4k+1)

= 2k^2 - k + 4k + 1

= 2k^2 + 3k + 1

= (k+1)(2k+1)

= (k+1)(2(k+1)-1)

**Answer this Question**

**Related Questions**

AP Calc - Use mathematical induction to prove that the statement holds for all ...

Mathematical induction. I'm stuck. So far I have.. - For all integers n ≥ ...

Calculus - Write the statements for the basis, the induction hypothesis, and the...

Math - Use mathematical induction to prove that 2^(3n) - 3^n is divisible by 5 ...

Calculus - Use mathematical induction to prove that each proposition is valid ...

Math - Mathematical Induction - 3. Prove by induction that∑_(r=1)^n▒...

Pre-cal - use mathematical induction to prove that 1^2 + 2^2 + 3^2 + ... + n^2...

Computer proof - Prove by induction on all positive integer k that if m is any ...

proof by mathematical induction - subject is PreCalulus. 2^(k+3) = and < (k+3...

Algebra II - In an induction proof of the statement 4+7+10+...+(3n-1)=n(3n+5)/2 ...