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November 22, 2014

November 22, 2014

Posted by **rolan** on Friday, August 10, 2012 at 5:46am.

- math -
**Reiny**, Friday, August 10, 2012 at 8:51amLet AB be the base, which will be a fixed length

AB = √(4^2 + 8^2) = √80

The height from C to line AB must be as long as possible, this is achieved when the slope of the tangent at C is the same as the slope of AB,

dy/dx = 2x

slope of AB = 8/4 = 2

then 2x = 2

x = 1

when x = 1, y = 1^2 = 1

C must be (1,1)

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