Posted by **Imalka** on Friday, August 10, 2012 at 4:56am.

Upon a flat only 10 m high (Is that possible?) there are two guns A and B attached together making a vertical angle of 60 degrees when A is flat on roof. They fire at the same time and has the same reloading time. Both guns are capable of giving an initial velocity of 5√3 to their bullets. If the 2nd bullet of A hits the 1st bullet of B in mid air, what's the reload time?

- Physics -
**bobpursley**, Friday, August 10, 2012 at 9:41am
You have to figure where they hit. They ave the same horizontal distance, and same vertical final height at times separated by reload time.

Vertical poistion:

A) h=10-1/2 g (t-R)^2 where t is time in air of B, and R is reloadt time.

B) h=10-5sqrt3sin60*t

That t puts them at the same vertical height. So you have three unknowns, vertical height, t, and R. You have two equa;tions.

Now considerhorizontal distance.

A) d=5sqrt3*(t-R)

B) d=5sqrt3*cos60*t

set these two eqaul to get

t-R=cos60t or 1.5t=R

Now you have three equations, three unknowns.

Have fun with the algebra. It should work out quickly.

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