Posted by Imalka on Friday, August 10, 2012 at 4:56am.
Upon a flat only 10 m high (Is that possible?) there are two guns A and B attached together making a vertical angle of 60 degrees when A is flat on roof. They fire at the same time and has the same reloading time. Both guns are capable of giving an initial velocity of 5√3 to their bullets. If the 2nd bullet of A hits the 1st bullet of B in mid air, what's the reload time?

Physics  bobpursley, Friday, August 10, 2012 at 9:41am
You have to figure where they hit. They ave the same horizontal distance, and same vertical final height at times separated by reload time.
Vertical poistion:
A) h=101/2 g (tR)^2 where t is time in air of B, and R is reloadt time.
B) h=105sqrt3sin60*t
That t puts them at the same vertical height. So you have three unknowns, vertical height, t, and R. You have two equa;tions.
Now considerhorizontal distance.
A) d=5sqrt3*(tR)
B) d=5sqrt3*cos60*t
set these two eqaul to get
tR=cos60t or 1.5t=R
Now you have three equations, three unknowns.
Have fun with the algebra. It should work out quickly.
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