Point E is on side AB of rectangle ABCD. If the area of ABCD is 48, what is the area of triangle CDE?
Since the height from E to CD does not change, the area of the triangel = 1/2 the area of the rectangle
= 24
To find the area of triangle CDE, we first need to find the length of side CD. Since ABCD is a rectangle, opposite sides are equal in length. Therefore, we can say that CD is equal to AB.
Since the area of ABCD is 48, we know that the length of AB multiplied by the width of AB is equal to 48. In other words, AB^2 = 48.
To find the length of AB, we can take the square root of 48.
√48 ≈ 6.9282
So, AB is approximately 6.9282.
Since CD is equal to AB, CD is also approximately 6.9282.
The area of triangle CDE can then be found using the formula for the area of a triangle, which is (base * height) / 2.
The base of the triangle is CD, which is approximately 6.9282.
The height of the triangle is DE. Since E is a point on AB, the height of the triangle is equal to the width of AB.
The width of AB is equal to the length of CD, which is approximately 6.9282.
Therefore, the area of triangle CDE is (6.9282 * 6.9282) / 2.
Calculating this, we get:
(6.9282 * 6.9282) / 2 ≈ 24.
So, the area of triangle CDE is approximately 24.