Friday

August 29, 2014

August 29, 2014

Posted by **Chad** on Thursday, August 9, 2012 at 10:14pm.

Ovincline. If the effective coefficient of friction between the ground and the box is 0.60, and the wind exerts a constant, horizontally-directed force of 5.0 N, how far up the incline will the box be blown by this wind before it

comes to a stop?

- Physics -
**Elena**, Friday, August 10, 2012 at 12:31pmHorizontal motion

m •a=F-μ•m•g.

a= (F-μ•m•g )/m=

=F/m - μ•g =5/0.5 – 0.6•9.8 = 4.12 m/s²

s1=at²/2 => t=sqrt(2•s/a) =1.7 s.

v=at=4.12•1.7 = 7.03 m/s.

The law of conservation of energy for incline:

mv²/2 +W(F) = W(fr) +ΔPE.

mv²/2 +F•x•cosθ = μ•m•g•cosθ•x+m•g•x•sinθ.

x= mv²/2{μ•m•g•cosθ-F•cosθ - m•g•sinθ} = 0.5 m.

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