Tuesday
March 28, 2017

Post a New Question

Posted by on .

three lamps connected to a 120-V AC (rms) household supply voltage. Lamps 1 and 2 have 75.0-W bulbs; lamp 3 has a 40.0-W bulb.

(a) For each bulb, find the rms current.
Irms, lamp 1 = A
Irms, lamp 2 = A
Irms, lamp 3 = A

(b) For each bulb, find the resistance.
Rlamp 1 = Ω
Rlamp 2 = Ω
Rlamp 3 = Ω

  • physics 102 - ,

    The lamps are in parallel and all have an applied voltage of 120 V (rms)

    (a) Irms = P/V
    where P is the lamp power rating in Watts.

    (b) V^2/R = P for each lamp
    R = V^2/P = 1.44*10^4/P ohms

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question