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Posted by on Thursday, August 9, 2012 at 3:56pm.

A tugboat goes 180 miles upstream in 15 hours. The return trip downstream takes 10 hours. find the speed of the tugboat without a current and the speed of the current

  • algebra - , Thursday, August 9, 2012 at 4:36pm

    distance=(velocityboat+vstream)time

    180=(vb+Vs)*10
    180=(Vb-Vs)*15


    divide both sides of a) by 10, and b) by 15

    18=vb+vs
    12=Vb-Vs

    add the equations
    30=2vb solve for vboat
    then put that into either equation and solve for vstream

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