Posted by **Anonymous** on Thursday, August 9, 2012 at 9:16am.

Given the following system is consistent

x+y=1

tx+y=t

(1+t)x+2y=3

Find the exact value of t.

- Math -
**Reiny**, Thursday, August 9, 2012 at 10:31am
subtract the first from the second

xt - x = t-1

x(t-1) = t-1

x = 1, if tÂ±1

in 1st:

1+y = 1

y = 0

in the last:

(1+t)(1) + 0 = 3

1+t = 3

t = 2

- Math -
**drwls**, Thursday, August 9, 2012 at 10:35am
Subtracting the first equation from the second gives you:

t-1 = (t-1)x

Therefore x = 1.

The first equation tells you that y = 0.

The third equation requires that

1 + t = 3

t = 2

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