Posted by Anonymous on Thursday, August 9, 2012 at 9:16am.
Given the following system is consistent
Find the exact value of t.
Math - Reiny, Thursday, August 9, 2012 at 10:31am
subtract the first from the second
xt - x = t-1
x(t-1) = t-1
x = 1, if t±1
1+y = 1
y = 0
in the last:
(1+t)(1) + 0 = 3
1+t = 3
t = 2
Math - drwls, Thursday, August 9, 2012 at 10:35am
Subtracting the first equation from the second gives you:
t-1 = (t-1)x
Therefore x = 1.
The first equation tells you that y = 0.
The third equation requires that
1 + t = 3
t = 2
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