Mr. R has some money to buy oranges, if he will buy 15 oranges he will need $90 more, if he will buy 10 oranges he will have $60 left. how much money has mr. R?
Let r=amount of money in dollars Mr. R has
and
x=cost of each orange
We will set up the equations
15x=r+90
10x=r-60
You can then solve for r and x by the method of elimination, substitution, or comparison.
Buying 5 more oranges costs an extra $150. Therefore they cost $30 each.
Buying ten oranges costs $300 and leaves him with $60. Therefore he started out with $360.
To find out how much money Mr. R has, we can set up a system of equations based on the given information.
Let's assume the cost of each orange is represented by 'x' dollars.
From the first condition, if Mr. R buys 15 oranges, he will need $90 more, we can write the equation:
15x + $90 = Total money Mr. R has
From the second condition, if Mr. R buys 10 oranges, he will have $60 left, we can write the equation:
Total money Mr. R has - 10x = $60
Now, we can solve these equations simultaneously.
15x + $90 = Total money Mr. R has
Total money Mr. R has - 10x = $60
Rearrange the equations to set them equal to zero:
15x - Total money Mr. R has + $90 = 0
-10x + Total money Mr. R has - $60 = 0
Combine like terms:
15x - Total money Mr. R has = -$90
-10x + Total money Mr. R has = $60
Now, we can add the equations together to eliminate the "Total money Mr. R has" term:
15x - Total money Mr. R has + (-10x + Total money Mr. R has) = -$90 + $60
Simplifying:
5x = -$30
To solve for 'x', divide both sides of the equation by 5:
x = -$30 / 5
x = -$6
Since the cost per orange cannot be negative, this implies that something is incorrect in the original question. Please double-check the given information to ensure its accuracy.