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March 31, 2015

March 31, 2015

Posted by **rolan** on Wednesday, August 8, 2012 at 10:29am.

- math -
**Steve**, Wednesday, August 8, 2012 at 10:43amthe height y of the ball at time t is

y = 15 - 5t^2

The shadow's position x meters from where the ball will hit, is found by using similar triangles:

y/x = 15/(9+x)

(15 - 5t^2)/x = 15/(9+x)

dx/dt = -(9+x)/t

at t = .5, x = 99, so

dx/dt = -(9+99)/(.5) = -216 m/s

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