physics
posted by akshara on .
a spring of force constant 'k' is cut into 2 parts whose lengths are in the ratio 1:2.The 2 parts are now connected in parallel and a block of mass 'm' is suspended at the end of the combined spring.find the period of oscillation performed by the block

Spring constant is inversely proportional to spring length. The original spring constant k becomes two springs with constants k1 = 3k and k2 = 3k/2, in parallel.
The effective spring constant of springs in parallel is obtaned by adding the separate spring constants; so the new spring constant becomes
k' = k1 + k2 = 9k/2.
The new period of oscillation is:
P = 2*pi*sqrt(m/k')
= 2*pi*sqrt(2/9)*sqrt(m/k)
= (2/3)*pi*sqrt(2m/k) 
how is k1=3k and k2=3k/2.i am getting it as k/3 and 2k/3