Posted by **akshara** on Wednesday, August 8, 2012 at 10:24am.

a spring of force constant 'k' is cut into 2 parts whose lengths are in the ratio 1:2.The 2 parts are now connected in parallel and a block of mass 'm' is suspended at the end of the combined spring.find the period of oscillation performed by the block

- physics -
**drwls**, Wednesday, August 8, 2012 at 12:06pm
Spring constant is inversely proportional to spring length. The original spring constant k becomes two springs with constants k1 = 3k and k2 = 3k/2, in parallel.

The effective spring constant of springs in parallel is obtaned by adding the separate spring constants; so the new spring constant becomes

k' = k1 + k2 = 9k/2.

The new period of oscillation is:

P = 2*pi*sqrt(m/k')

= 2*pi*sqrt(2/9)*sqrt(m/k)

= (2/3)*pi*sqrt(2m/k)

- physics -
**akshara**, Wednesday, August 8, 2012 at 12:16pm
how is k1=3k and k2=3k/2.i am getting it as k/3 and 2k/3

## Answer This Question

## Related Questions

- PHYSICS - Q.1.A spring of force constant'k'is cut into two parts whoose lengths ...
- Physics - A light spring of force constant 8N/m is cut into two equal parts and ...
- Physics - Two springs, each with spring constant 20 N/m, are connected in ...
- Science - A piece of wire of resistance R and cut into five equal parts. These ...
- Physics - A block is suspended from the end of a spring. An external force holds...
- math - A string is cut into two parts.The ratio of lengths of the string and the...
- PHYSICS - An object of mass M is divided into two parts ,which are placed at ...
- physics - A solid block of mass m2 = 1.0 $kg$, at rest on a horizontal ...
- physics - A spring of force constant k is cut into two equal parts. what is the ...
- physics - In Figure (a), a block of mass m lies on a horizontal frictionless ...

More Related Questions