A professional basketball team has won 50 out of the 75 games played so far.The team still has 45 games to play.How many of these games must the team play in order to have a season record of winning 60% of the games played?

Do you mean "How many of these games must the team WIN in order . . ."?

yea

0.6(75 + 45) = 72

72 - 50 = ?

Thanks :]

You're welcome.

To determine how many games the team must win out of the remaining 45 games in order to have a season record of winning 60% of the games played, we first need to find out the total number of games played in the season so far.

Since the team has won 50 games out of 75 played, their current winning percentage can be calculated by dividing the number of games won by the total number of games played:

Current winning percentage = (Number of games won / Total number of games played) * 100

Current winning percentage = (50 / 75) * 100

Current winning percentage = 66.67%

Now, let's calculate the number of games needed to achieve a winning percentage of 60%.

Let W represent the number of games won in the remaining 45 games, then the equation becomes:

(50 + W) / (75 + 45) = 60 / 100

Now we can solve for W:

(50 + W) / 120 = 60 / 100

Cross-multiplying, we get:

100 * (50 + W) = 60 * 120

5000 + 100W = 7200

100W = 7200 - 5000

100W = 2200

W = 2200 / 100

W = 22

Therefore, the team must win 22 out of the remaining 45 games in order to have a season record of winning 60% of the games played.