Tuesday

March 31, 2015

March 31, 2015

Posted by **Paul** on Tuesday, August 7, 2012 at 5:53pm.

a = 1 and b = 4

integral of

(1 - 1/x^2)(x^2 + 1/x) dx

= (x + 1/x)(x^3/3 + lnx) + C

(4 + 1/4)(64/3 + ln4) - (1 + 1)(1/3 + ln1)

= 96.56 - 0.6666 = 95.89

THank you

- Calculus - Verification -
**Damon**, Tuesday, August 7, 2012 at 6:06pmI do not think so. Multiply out and integrate each term.

- Calculus - Verification -
**Damon**, Tuesday, August 7, 2012 at 6:07pm(x^2 -1 + 1/x -1/x^3)dx

x^2 dx - dx + dx/x - dx/x^3

x^3/3 etc

- Calculus - Verification -
**Damon**, Tuesday, August 7, 2012 at 6:08pmintegral a b dx is not integral a dx * integral b dx

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