Posted by **Anonymous** on Tuesday, August 7, 2012 at 4:53pm.

(integral) e^3x dx

A. e^3x+C

B. 1/3e^3x+C

C. e^4x+C

D. 1/4e^4x+C

Evaluate (integral) dx/(Square root 9-8x-x^2)

A. sin^-1(x+4/5)+C

B. sin^-1(x-4/5)+C

C. Ln(Square root 9-8x-x^2)+C

D. Ln(-8-2x)+C

- Calculus -
**Anonymous**, Tuesday, August 7, 2012 at 5:39pm
if u = 3x you have integral e^u du/3, so (B)

since 9-8x-x^2 = 25 - (x+4)^2, and integral du/sqrt(a^2-u^2) = arcsin(u/a), you have arcsin u/5, so (A)

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