Posted by ibranian on Tuesday, August 7, 2012 at 1:31pm.
clearly the weight of the box is a function of the material used, which in turn depends on the surface area of the sheet metal used.
So we want a minimum surface area.
let each side of the base be x ft, and let the height be y ft.
Area = x^2 + 4xy
but x^2 y = 500
y = 500/x^2
area = x^2 + 4x(500/x^2) = x^2 + 2000/x
d(area)/dx = 2x -2000/x^2 = 0 for a min of area
2x = 2000/x^2
x^3 = 1000
x = 10 , then y = 500/10^2 = 5
the box should have a base of 10 ft by 10 ft, and a height of 5 ft.
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