Wednesday

November 26, 2014

November 26, 2014

Posted by **ibranian** on Tuesday, August 7, 2012 at 5:16am.

- math -
**Reiny**, Tuesday, August 7, 2012 at 8:22amProfit = 2(x) + 1(40-10x)/(5-x)

= 2x + (40-10x)/(5-x)

= (2x^2 - 40)/(x-5)

d(profit)/dx = [(x-5)(4x) - (2x^2 - 40)(1) ]/(x-5)^2

= 0 for a max of profit

4x^2 - 20x - 2x^2 + 40 = 0

x^2 - 10x + 20 = 0

x = 5 ± √5

= appr 7.24 or appr 2.76

but x must be between 0 and 4, so x = 2.76

where x is in hundreds

so for a max profit they should make 276 A tires

and 552 B tires

check my arithmetic,

- math -
**lamar henderson**, Tuesday, August 14, 2012 at 3:17pm(3,0),(-2,6),(1,5),(3,6)

**Answer this Question**

**Related Questions**

Calculus - P(x)= -x^3+15x^2-48x+450, x>/3 is an approximation to the total ...

algebra 1 help please - 4) a student score is 83 and 91 on her first two quizzes...

math - 20. A tire company manufactures 50 tires an hour with its current staff. ...

math - A tire company determines that to manufacture a certain type of tire, it ...

math - A company has two factories that manufacture tires. Suppose 65% of the ...

Grade 12 Calculus - Determine the absolute extrema of each function on the ...

Grade 12 Calculus - Determine the absolute extrema of each function on the ...

Grade 12 Calculus - Determine the absolute extrema of each function on the ...

Grade 12 Calculus - Determine the absolute extrema of each function on the ...

3rd grade math - A 16 wheler truck has 16 tires. The cab of a 16 wheeler has 6 ...