Posted by Robert on .
Solve the differential equation dy/dx = xe^y and determine the equation of the curve through P(1,2)
I tried solving the differential equation and I get y = log(x^2/2 + C).
Is this correct?
Now I forgot how to find the equation.
Thank you!

Calculus 
MathMate,
Your solution is almost good, just a change of the sign will fix it.
y=log(x^2/2+C)
If it has to pass through P(1,2)
substitute x=1, and y=2 and find C.
2=log(1/2+C)
log(1/2+C)=2
take logs
1/2+C=e^(2)
C=e^(2)1/2
so
y=log(x²/2+e^(2)1/2) 
Calculus 
Paul,
thanks a lot mate

Calculus 
Robert,
oops, that was under my brother's name hehe

Calculus :) 
MathMate,
You're both welcome!