The perimeter of a soccer field is 280yd. The width is 5yd more than half the length. Can you help me with the formula to solve this problem?

P = 2L + 2W

280 = 2L + 2(0.5L + 5)

280 = 2L + L + 10

280 = 3L + 10

270 = 3L

90 = L

Sure, here's the step-by-step approach to solving this problem:

Step 1: Assign variables
Let's assign variables to the given information. Let L represent the length of the soccer field, and W represent the width.

Step 2: Translate the given information into equations
The first piece of information states that the perimeter of the soccer field is 280 yards. Essentially, the perimeter is the sum of all four sides of the rectangle.

The formula for the perimeter of a rectangle is: P = 2L + 2W.
Therefore, we can write the equation as:
2L + 2W = 280

The second piece of information states that the width is 5 yards more than half the length. We can express this as:
W = (1/2)L + 5

Step 3: Substitute the value of W from the second equation into the first equation
Substitute (1/2)L + 5 for W in the equation 2L + 2W = 280:
2L + 2((1/2)L + 5) = 280

Step 4: Simplify and solve the equation
Distribute the 2:
2L + L + 10 = 280
3L + 10 = 280

Subtract 10 from both sides:
3L = 270

Divide both sides by 3:
L = 90

Step 5: Find the value of W
Substitute the value of L into the second equation:
W = (1/2)(90) + 5
W = 45 + 5
W = 50

Step 6: Check your answer
To check if our solution is correct, substitute the values of L and W into the first equation:
2(90) + 2(50) = 280
180 + 100 = 280
280 = 280

Since the equation is true, our solution is correct.

Therefore, the length of the soccer field is 90 yards and the width is 50 yards.

Certainly! To solve this problem, we'll set up a couple of equations based on the given information.

Let's start by assigning variables:

Let L be the length of the soccer field.
Then the width would be expressed as (1/2)L + 5.

The perimeter of a rectangle is calculated by adding up the lengths of all four sides. In this case, it is given that the perimeter is 280 yards.

So, the perimeter equation can be written as:

2(L + (1/2)L + 5) = 280

Simplifying the equation:

2.5L + 10 = 280

Next, we can isolate L by subtracting 10 from both sides:

2.5L = 270

Finally, divide both sides by 2.5 to solve for L:

L = 270 / 2.5

Therefore, the length of the soccer field is L ≈ 108 yards.

Since the width is (1/2)L + 5, we can substitute the value of L we found:

Width = (1/2)(108) + 5

Width ≈ 54 + 5

Thus, the width of the soccer field is approximately 59 yards.