Posted by Anonymous on Sunday, August 5, 2012 at 3:43pm.
solve the equation 3 cos t = 1 in the interval from 0 to 2p?

Algebra 2  MathMate, Sunday, August 5, 2012 at 4:06pm
3 cos t = 1
cos(t)=(1/3)
Look at the plot of cos(t) between 0 and 2π, and note that there are two solutions between π/2 and 3π/2 where cos(t) is negative.

Algebra 2  Anonymous, Sunday, August 5, 2012 at 4:27pm
1. function g(x)=x^23x+7 . Find the area under the curve for the domain –4£ x £ 1.
a 71.6 square units
b. 46 square units
c.35.83 square units
d.17.916square units

Algebra 2  MathMate, Sunday, August 5, 2012 at 5:07pm
∫x^23x+7dx between 4 and 1
to evaluate
[x³/3(3/2)x²+7x] between 4 and 1.
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