Posted by **Anonymous** on Sunday, August 5, 2012 at 3:43pm.

solve the equation -3 cos t = 1 in the interval from 0 to 2p?

- Algebra 2 -
**MathMate**, Sunday, August 5, 2012 at 4:06pm
-3 cos t = 1

cos(t)=-(1/3)

Look at the plot of cos(t) between 0 and 2π, and note that there are two solutions between π/2 and 3π/2 where cos(t) is negative.

- Algebra 2 -
**Anonymous**, Sunday, August 5, 2012 at 4:27pm
1. function g(x)=-x^2-3x+7 . Find the area under the curve for the domain –4£ x £ 1.

a 71.6 square units

b. 46 square units

c.35.83 square units

d.17.916square units

- Algebra 2 -
**MathMate**, Sunday, August 5, 2012 at 5:07pm
∫-x^2-3x+7dx between -4 and 1

to evaluate

[-x³/3-(3/2)x²+7x] between -4 and 1.

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