Posted by Cynthia on Saturday, August 4, 2012 at 9:44pm.
to evaluate (integral) 3x^2 cos (2x^34) dx, it is necessary to let
A. u=3x^2
B. u=6x
C. u=2x^34
D. u=6x^2

Calculus  Steve, Sunday, August 5, 2012 at 6:36am
C
then du = 2(3x^2) dx
Answer This Question
Related Questions
 Calculus  I have two questions, because I'm preparing for a math test on monday...
 Calculus  Evaluate the definite Integral Integral [0 to pi/4] cos(2x)sec^2(pi/4...
 calculus  Evaluate the indefinite integral. integral of 8 sin^4 x cos x dx
 Integral  That's the same as the integral of sin^2 x dx. Use integration by ...
 Calculus  Evaluate (Integral) sin 4x cos^2 4x dx. A. Cos^3(4x)/3 + C B. Cos^3(...
 Calculus  Evaluate the integral sin4x cos^2 4x dx A. cos^3 4x/3 +C B.  cos^3 ...
 Calculus II  Evaluate using usubstitution: Integral of: 4x(tan(x^2))dx ...
 Calculus  Evaluate the integral. S= integral sign I= absolute value S ((cos x...
 Calculus  Use the identity sin^2x+cos^2x=1 and the fact that sin^2x and cos^2x ...
 Calculus  Use the identity sin^2x+cos^2x=1 and the fact that sin^2x and cos^2x ...
More Related Questions