Posted by Cynthia on Saturday, August 4, 2012 at 9:44pm.
to evaluate (integral) 3x^2 cos (2x^34) dx, it is necessary to let
A. u=3x^2
B. u=6x
C. u=2x^34
D. u=6x^2

Calculus  Steve, Sunday, August 5, 2012 at 6:36am
C
then du = 2(3x^2) dx