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March 29, 2015

March 29, 2015

Posted by **Cynthia** on Saturday, August 4, 2012 at 9:12pm.

A. 1/2Ln sin 2x+C

B. 1/2Ln cos 2x+C

C. 1/2Ln sec 2x+C

D. 1/2LN csc 2x+C

- Calculus -
**MathMate**, Saturday, August 4, 2012 at 11:38pmFirst make the substitution

p=2x,

dp=2dx

dx=(1/2)dp

I=∫cot 2x dx

=∫cot(p)(1/2)dp

=(1/2)∫(cos(p)/sin(p))dp

=(1/2)∫d(sin(p))/sin(p)

=(1/2)ln sin(p) + C

Can you take it from here?

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