How many moles of chloride ions are present in 18.4g of CaCl2?
I don't know how to set this up...
Don't let problems like this confuse you. First mols CaCl2 = grams CaCl2/molar mass CaCl2. Then mols Cl^- is twice that.
To calculate the number of moles of chloride ions present in 18.4g of CaCl2, you need to follow these steps:
Step 1: Find the molar mass of CaCl2.
The molar mass is the mass of one mole of a substance. The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol. Since CaCl2 has one calcium atom and two chlorine atoms, the molar mass of CaCl2 can be calculated as follows:
Molar mass of CaCl2 = 1 x molar mass of Ca + 2 x molar mass of Cl
Molar mass of CaCl2 = 1 x 40.08 g/mol + 2 x 35.45 g/mol
Step 2: Calculate the number of moles of CaCl2.
To find the number of moles, divide the given mass by the molar mass:
Number of moles of CaCl2 = Mass of CaCl2 / Molar mass of CaCl2
Number of moles of CaCl2 = 18.4 g / (40.08 g/mol + 2 x 35.45 g/mol)
Step 3: Calculate the moles of chloride ions.
Since there are two chloride ions in one molecule of CaCl2, the moles of chloride ions can be determined by multiplying the calculated moles of CaCl2 by 2.
Moles of chloride ions = Number of moles of CaCl2 x 2
By following these steps, you will be able to determine the number of moles of chloride ions present in 18.4g of CaCl2.