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Prove that 1+tan(Theta)/1-tan(Theta) = sec^2(Theta)+2tan(Theta)/1-tan^2(Theta)

If you explain, that would be great (:

  • Trigonometry - ,


    multiply top and bottom by 1+tan

    (1+tan)^2 / (1-tan)(1+tan)

    (1 + 2tan + tan^2)/(1-tan^2)

    now, since sec^2 = 1+tan^2,

    (sec^2 + 2tan)/(1-tan^2)

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