Thursday

September 3, 2015
Posted by **Marie** on Friday, August 3, 2012 at 3:31pm.

If you explain, that would be great (:

- Trigonometry -
**Steve**, Friday, August 3, 2012 at 3:50pm(1+tan)/(1-tan)

multiply top and bottom by 1+tan

(1+tan)^2 / (1-tan)(1+tan)

(1 + 2tan + tan^2)/(1-tan^2)

now, since sec^2 = 1+tan^2,

(sec^2 + 2tan)/(1-tan^2)