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July 30, 2014

July 30, 2014

Posted by **shivankar** on Friday, August 3, 2012 at 1:08pm.

- dynamics -
**drwls**, Friday, August 3, 2012 at 8:41pmI assume that you mean a point on the rim, not a print. The radial and tangential acceleration components are perpendicular. Therefore

(3.5)^2 = (4 R)^2 + [ 3^2*R]^2

The first term on the right is the square of the tangential acceleration. The second term is the square of the centripetal acceleration.

Solve for R.

- dynamics -
**ajay**, Sunday, August 5, 2012 at 10:20pm13. The constant angular acceleration of a pulley is 4 rad/s2 and its angular speed its 3 rad/s. Determine the radius of the pulley if the total acceleration of a print on the rim of the pulley is 3.5m/s2.

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